Distance from Oxon Hill to Boortmeerbeek
The shortest distance (air line) between Oxon Hill and Boortmeerbeek is 3,870.51 mi (6,228.99 km).
How far is Oxon Hill from Boortmeerbeek
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 01:42 (04.02.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 07:42 (04.02.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 3,870.51 miles which is equal to 6,228.99 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Boortmeerbeek, Arr. Leuven, Belgium