Distance from Oxon Hill to Borgerhout
The shortest distance (air line) between Oxon Hill and Borgerhout is 3,859.65 mi (6,211.50 km).
How far is Oxon Hill from Borgerhout
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 01:54 (04.02.2025)
Borgerhout is located in Arr. Antwerpen, Belgium within 51° 12' 42.12" N 4° 26' 26.52" E (51.2117, 4.4407) coordinates. The local time in Borgerhout is 07:54 (04.02.2025)
The calculated flying distance from Borgerhout to Borgerhout is 3,859.65 miles which is equal to 6,211.50 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Borgerhout, Arr. Antwerpen, Belgium