Distance from Oxon Hill to Buggenhout
The shortest distance (air line) between Oxon Hill and Buggenhout is 3,855.25 mi (6,204.43 km).
How far is Oxon Hill from Buggenhout
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 02:04 (04.02.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 08:04 (04.02.2025)
The calculated flying distance from Buggenhout to Buggenhout is 3,855.25 miles which is equal to 6,204.43 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Buggenhout, Arr. Dendermonde, Belgium