Distance from Oxon Hill to Castelnuovo di Porto
The shortest distance (air line) between Oxon Hill and Castelnuovo di Porto is 4,478.14 mi (7,206.86 km).
How far is Oxon Hill from Castelnuovo di Porto
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 20:33 (04.03.2025)
Castelnuovo di Porto is located in Roma, Italy within 42° 7' 59.88" N 12° 30' 0" E (42.1333, 12.5000) coordinates. The local time in Castelnuovo di Porto is 02:33 (05.03.2025)
The calculated flying distance from Castelnuovo di Porto to Castelnuovo di Porto is 4,478.14 miles which is equal to 7,206.86 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Castelnuovo di Porto, Roma, Italy