Distance from Oxon Hill to Celakovice
The shortest distance (air line) between Oxon Hill and Celakovice is 4,299.33 mi (6,919.10 km).
How far is Oxon Hill from Celakovice
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 21:49 (11.02.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 03:49 (12.02.2025)
The calculated flying distance from Celakovice to Celakovice is 4,299.33 miles which is equal to 6,919.10 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Celakovice, Středočeský kraj, Czechia