Distance from Oxon Hill to Oud-Turnhout
The shortest distance (air line) between Oxon Hill and Oud-Turnhout is 3,878.81 mi (6,242.34 km).
How far is Oxon Hill from Oud-Turnhout
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 01:23 (11.02.2025)
Oud-Turnhout is located in Arr. Turnhout, Belgium within 51° 19' 0.12" N 4° 58' 59.88" E (51.3167, 4.9833) coordinates. The local time in Oud-Turnhout is 07:23 (11.02.2025)
The calculated flying distance from Oud-Turnhout to Oud-Turnhout is 3,878.81 miles which is equal to 6,242.34 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Oud-Turnhout, Arr. Turnhout, Belgium