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      Distance from Oxon Hill to San Ferdinando di Puglia

      The shortest distance (air line) between Oxon Hill and San Ferdinando di Puglia is 4,664.99 mi (7,507.57 km).

      How far is Oxon Hill from San Ferdinando di Puglia

      Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 03:58 (10.03.2025)

      San Ferdinando di Puglia is located in Barletta-Andria-Trani, Italy within 41° 17' 60" N 16° 4' 0.12" E (41.3000, 16.0667) coordinates. The local time in San Ferdinando di Puglia is 09:58 (10.03.2025)

      The calculated flying distance from San Ferdinando di Puglia to San Ferdinando di Puglia is 4,664.99 miles which is equal to 7,507.57 km.

      Oxon Hill, Maryland, United States

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      San Ferdinando di Puglia, Barletta-Andria-Trani, Italy

      Related Distances to San Ferdinando di Puglia