Distance from Oxon Hill to San Gennaro Vesuviano
The shortest distance (air line) between Oxon Hill and San Gennaro Vesuviano is 4,613.49 mi (7,424.70 km).
How far is Oxon Hill from San Gennaro Vesuviano
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 04:26 (10.03.2025)
San Gennaro Vesuviano is located in Napoli, Italy within 40° 52' 0.12" N 14° 31' 59.88" E (40.8667, 14.5333) coordinates. The local time in San Gennaro Vesuviano is 10:26 (10.03.2025)
The calculated flying distance from San Gennaro Vesuviano to San Gennaro Vesuviano is 4,613.49 miles which is equal to 7,424.70 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
San Gennaro Vesuviano, Napoli, Italy