Distance from Oxon Hill to San Giorgio del Sannio
The shortest distance (air line) between Oxon Hill and San Giorgio del Sannio is 4,620.16 mi (7,435.43 km).
How far is Oxon Hill from San Giorgio del Sannio
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 04:18 (10.03.2025)
San Giorgio del Sannio is located in Benevento, Italy within 41° 4' 0.12" N 14° 50' 60" E (41.0667, 14.8500) coordinates. The local time in San Giorgio del Sannio is 10:18 (10.03.2025)
The calculated flying distance from San Giorgio del Sannio to San Giorgio del Sannio is 4,620.16 miles which is equal to 7,435.43 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
San Giorgio del Sannio, Benevento, Italy