Distance from Oxon Hill to San Giovanni la Punta
The shortest distance (air line) between Oxon Hill and San Giovanni la Punta is 4,761.63 mi (7,663.10 km).
How far is Oxon Hill from San Giovanni la Punta
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 04:05 (10.03.2025)
San Giovanni la Punta is located in Catania, Italy within 37° 34' 59.88" N 15° 5' 60" E (37.5833, 15.1000) coordinates. The local time in San Giovanni la Punta is 10:05 (10.03.2025)
The calculated flying distance from San Giovanni la Punta to San Giovanni la Punta is 4,761.63 miles which is equal to 7,663.10 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
San Giovanni la Punta, Catania, Italy