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      Distance from Oxon Hill to San Gregorio di Catania

      The shortest distance (air line) between Oxon Hill and San Gregorio di Catania is 4,763.02 mi (7,665.35 km).

      How far is Oxon Hill from San Gregorio di Catania

      Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 03:26 (10.03.2025)

      San Gregorio di Catania is located in Catania, Italy within 37° 34' 0.12" N 15° 7' 0.12" E (37.5667, 15.1167) coordinates. The local time in San Gregorio di Catania is 09:26 (10.03.2025)

      The calculated flying distance from San Gregorio di Catania to San Gregorio di Catania is 4,763.02 miles which is equal to 7,665.35 km.

      Oxon Hill, Maryland, United States

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      San Gregorio di Catania, Catania, Italy

      Related Distances to San Gregorio di Catania