Distance from Oxon Hill to San Lazzaro di Savena
The shortest distance (air line) between Oxon Hill and San Lazzaro di Savena is 4,350.13 mi (7,000.86 km).
How far is Oxon Hill from San Lazzaro di Savena
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 03:23 (10.03.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 09:23 (10.03.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,350.13 miles which is equal to 7,000.86 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
San Lazzaro di Savena, Bologna, Italy