Distance from Oxon Hill to Sendenhorst
The shortest distance (air line) between Oxon Hill and Sendenhorst is 3,977.86 mi (6,401.75 km).
How far is Oxon Hill from Sendenhorst
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 15:30 (28.02.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 21:30 (28.02.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 3,977.86 miles which is equal to 6,401.75 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Sendenhorst, Warendorf, Germany