Distance from Oxon Hill to Sint-Joost-ten-Node
The shortest distance (air line) between Oxon Hill and Sint-Joost-ten-Node is 3,866.47 mi (6,222.49 km).
How far is Oxon Hill from Sint-Joost-ten-Node
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 01:38 (11.02.2025)
Sint-Joost-ten-Node is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 51' 0" N 4° 22' 59.88" E (50.8500, 4.3833) coordinates. The local time in Sint-Joost-ten-Node is 07:38 (11.02.2025)
The calculated flying distance from Sint-Joost-ten-Node to Sint-Joost-ten-Node is 3,866.47 miles which is equal to 6,222.49 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Sint-Joost-ten-Node, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium