Distance from Oxon Hill to Sint-Katelijne-Waver
The shortest distance (air line) between Oxon Hill and Sint-Katelijne-Waver is 3,867.05 mi (6,223.41 km).
How far is Oxon Hill from Sint-Katelijne-Waver
Oxon Hill is located in Maryland, United States within 38° 47' 18.24" N -77° 1' 38.28" W (38.7884, -76.9727) coordinates. The local time in Oxon Hill is 01:22 (11.02.2025)
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 07:22 (11.02.2025)
The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 3,867.05 miles which is equal to 6,223.41 km.
Oxon Hill, Maryland, United States
Related Distances from Oxon Hill
Sint-Katelijne-Waver, Arr. Mechelen, Belgium