Distance from Ozarow Mazowiecki to Sint-Kruis
The shortest distance (air line) between Ozarow Mazowiecki and Sint-Kruis is 752.64 mi (1,211.26 km).
How far is Ozarow Mazowiecki from Sint-Kruis
Ozarow Mazowiecki is located in Warszawski zachodni, Poland within 52° 13' 0.12" N 20° 48' 0" E (52.2167, 20.8000) coordinates. The local time in Ozarow Mazowiecki is 00:16 (25.11.2024)
Sint-Kruis is located in Arr. Brugge, Belgium within 51° 12' 42.12" N 3° 15' 0" E (51.2117, 3.2500) coordinates. The local time in Sint-Kruis is 00:16 (25.11.2024)
The calculated flying distance from Sint-Kruis to Sint-Kruis is 752.64 miles which is equal to 1,211.26 km.
Ozarow Mazowiecki, Warszawski zachodni, Poland
Related Distances from Ozarow Mazowiecki
Sint-Kruis, Arr. Brugge, Belgium