Distance from Paducah to Alexandroupoli
The shortest distance (air line) between Paducah and Alexandroupoli is 5,646.76 mi (9,087.59 km).
How far is Paducah from Alexandroupoli
Paducah is located in Kentucky, United States within 37° 4' 15.96" N -89° 21' 21.6" W (37.0711, -88.6440) coordinates. The local time in Paducah is 05:48 (24.02.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 13:48 (24.02.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 5,646.76 miles which is equal to 9,087.59 km.
Paducah, Kentucky, United States