Distance from Painesville to Begijnendijk
The shortest distance (air line) between Painesville and Begijnendijk is 3,913.93 mi (6,298.86 km).
How far is Painesville from Begijnendijk
Painesville is located in Ohio, United States within 41° 43' 26.4" N -82° 44' 47.04" W (41.7240, -81.2536) coordinates. The local time in Painesville is 08:30 (26.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 14:30 (26.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,913.93 miles which is equal to 6,298.86 km.
Painesville, Ohio, United States
Related Distances from Painesville
Begijnendijk, Arr. Leuven, Belgium