Distance from Palm City to Buggenhout
The shortest distance (air line) between Palm City and Buggenhout is 4,551.62 mi (7,325.12 km).
How far is Palm City from Buggenhout
Palm City is located in Florida, United States within 27° 10' 24.6" N -81° 42' 49.68" W (27.1735, -80.2862) coordinates. The local time in Palm City is 05:53 (10.02.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 11:53 (10.02.2025)
The calculated flying distance from Buggenhout to Buggenhout is 4,551.62 miles which is equal to 7,325.12 km.
Palm City, Florida, United States
Related Distances from Palm City
Buggenhout, Arr. Dendermonde, Belgium