Distance from Palm Harbor to Begijnendijk
The shortest distance (air line) between Palm Harbor and Begijnendijk is 4,633.06 mi (7,456.18 km).
How far is Palm Harbor from Begijnendijk
Palm Harbor is located in Florida, United States within 28° 5' 4.92" N -83° 15' 6.84" W (28.0847, -82.7481) coordinates. The local time in Palm Harbor is 08:24 (22.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 14:24 (22.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,633.06 miles which is equal to 7,456.18 km.
Palm Harbor, Florida, United States
Related Distances from Palm Harbor
Begijnendijk, Arr. Leuven, Belgium