Distance from Palma di Montechiaro to Petersburg
The shortest distance (air line) between Palma di Montechiaro and Petersburg is 4,791.40 mi (7,711.02 km).
How far is Palma di Montechiaro from Petersburg
Palma di Montechiaro is located in Agrigento, Italy within 37° 11' 36.96" N 13° 45' 56.88" E (37.1936, 13.7658) coordinates. The local time in Palma di Montechiaro is 13:04 (04.10.2025)
Petersburg is located in Virginia, United States within 37° 12' 15.48" N -78° 36' 31.32" W (37.2043, -77.3913) coordinates. The local time in Petersburg is 07:04 (04.10.2025)
The calculated flying distance from Petersburg to Petersburg is 4,791.40 miles which is equal to 7,711.02 km.
Palma di Montechiaro, Agrigento, Italy
Related Distances from Palma di Montechiaro
Petersburg, Virginia, United States