Distance from Panama City to Aleksandrow Lodzki
The shortest distance (air line) between Panama City and Aleksandrow Lodzki is 5,185.39 mi (8,345.08 km).
How far is Panama City from Aleksandrow Lodzki
Panama City is located in Florida, United States within 30° 11' 58.2" N -86° 23' 58.92" W (30.1995, -85.6003) coordinates. The local time in Panama City is 02:54 (17.12.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 09:54 (17.12.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,185.39 miles which is equal to 8,345.08 km.
Panama City, Florida, United States
Related Distances from Panama City
Aleksandrow Lodzki, Łódzki, Poland