Distance from Panama City to Janow Lubelski
The shortest distance (air line) between Panama City and Janow Lubelski is 5,339.93 mi (8,593.79 km).
How far is Panama City from Janow Lubelski
Panama City is located in Florida, United States within 30° 11' 58.2" N -86° 23' 58.92" W (30.1995, -85.6003) coordinates. The local time in Panama City is 16:34 (17.12.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 23:34 (17.12.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 5,339.93 miles which is equal to 8,593.79 km.
Panama City, Florida, United States
Related Distances from Panama City
Janow Lubelski, Puławski, Poland