Distance from Parkersburg to Diepenbeek
The shortest distance (air line) between Parkersburg and Diepenbeek is 4,067.05 mi (6,545.28 km).
How far is Parkersburg from Diepenbeek
Parkersburg is located in West Virginia, United States within 39° 15' 44.28" N -82° 27' 28.8" W (39.2623, -81.5420) coordinates. The local time in Parkersburg is 21:36 (04.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 03:36 (05.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,067.05 miles which is equal to 6,545.28 km.
Parkersburg, West Virginia, United States
Related Distances from Parkersburg
Diepenbeek, Arr. Hasselt, Belgium