Distance from Parkersburg to Kalmthout
The shortest distance (air line) between Parkersburg and Kalmthout is 4,015.80 mi (6,462.80 km).
How far is Parkersburg from Kalmthout
Parkersburg is located in West Virginia, United States within 39° 15' 44.28" N -82° 27' 28.8" W (39.2623, -81.5420) coordinates. The local time in Parkersburg is 14:13 (10.02.2025)
Kalmthout is located in Arr. Antwerpen, Belgium within 51° 22' 59.88" N 4° 28' 0.12" E (51.3833, 4.4667) coordinates. The local time in Kalmthout is 20:13 (10.02.2025)
The calculated flying distance from Kalmthout to Kalmthout is 4,015.80 miles which is equal to 6,462.80 km.
Parkersburg, West Virginia, United States
Related Distances from Parkersburg
Kalmthout, Arr. Antwerpen, Belgium