Distance from Parkersburg to Sint-Katelijne-Waver
The shortest distance (air line) between Parkersburg and Sint-Katelijne-Waver is 4,027.55 mi (6,481.71 km).
How far is Parkersburg from Sint-Katelijne-Waver
Parkersburg is located in West Virginia, United States within 39° 15' 44.28" N -82° 27' 28.8" W (39.2623, -81.5420) coordinates. The local time in Parkersburg is 09:08 (05.02.2025)
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 15:08 (05.02.2025)
The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 4,027.55 miles which is equal to 6,481.71 km.
Parkersburg, West Virginia, United States
Related Distances from Parkersburg
Sint-Katelijne-Waver, Arr. Mechelen, Belgium