Distance from Parkersburg to Sveti Ivan Zelina
The shortest distance (air line) between Parkersburg and Sveti Ivan Zelina is 4,666.59 mi (7,510.15 km).
How far is Parkersburg from Sveti Ivan Zelina
Parkersburg is located in West Virginia, United States within 39° 15' 44.28" N -82° 27' 28.8" W (39.2623, -81.5420) coordinates. The local time in Parkersburg is 20:55 (05.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 02:55 (06.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,666.59 miles which is equal to 7,510.15 km.
Parkersburg, West Virginia, United States
Related Distances from Parkersburg
Sveti Ivan Zelina, Zagrebačka županija, Croatia