Distance from Parole to Aleksandrovac
The shortest distance (air line) between Parole and Aleksandrovac is 4,768.77 mi (7,674.59 km).
How far is Parole from Aleksandrovac
Parole is located in Maryland, United States within 38° 59' 10.68" N -77° 26' 53.52" W (38.9863, -76.5518) coordinates. The local time in Parole is 12:54 (06.06.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 18:54 (06.06.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 4,768.77 miles which is equal to 7,674.59 km.
Parole, Maryland, United States
Related Distances from Parole
Aleksandrovac, Rasinska oblast, Serbia