Distance from Parole to Aleksandrow Lodzki
The shortest distance (air line) between Parole and Aleksandrow Lodzki is 4,390.42 mi (7,065.69 km).
How far is Parole from Aleksandrow Lodzki
Parole is located in Maryland, United States within 38° 59' 10.68" N -77° 26' 53.52" W (38.9863, -76.5518) coordinates. The local time in Parole is 08:38 (23.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 14:38 (23.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,390.42 miles which is equal to 7,065.69 km.
Parole, Maryland, United States
Related Distances from Parole
Aleksandrow Lodzki, Łódzki, Poland