Distance from Patchogue to Begijnendijk
The shortest distance (air line) between Patchogue and Begijnendijk is 3,630.15 mi (5,842.17 km).
How far is Patchogue from Begijnendijk
Patchogue is located in New York, United States within 40° 45' 43.56" N -74° 58' 53.4" W (40.7621, -73.0185) coordinates. The local time in Patchogue is 14:16 (11.04.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 20:16 (11.04.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,630.15 miles which is equal to 5,842.17 km.
Patchogue, New York, United States
Related Distances from Patchogue
Begijnendijk, Arr. Leuven, Belgium