Distance from Patchogue to Steenokkerzeel
The shortest distance (air line) between Patchogue and Steenokkerzeel is 3,621.40 mi (5,828.08 km).
How far is Patchogue from Steenokkerzeel
Patchogue is located in New York, United States within 40° 45' 43.56" N -74° 58' 53.4" W (40.7621, -73.0185) coordinates. The local time in Patchogue is 10:02 (27.04.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 16:02 (27.04.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,621.40 miles which is equal to 5,828.08 km.
Patchogue, New York, United States
Related Distances from Patchogue
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium