Distance from Peekskill to Aleksandrow Lodzki
The shortest distance (air line) between Peekskill and Aleksandrow Lodzki is 4,179.60 mi (6,726.42 km).
How far is Peekskill from Aleksandrow Lodzki
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 15:12 (17.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 21:12 (17.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,179.60 miles which is equal to 6,726.42 km.
Peekskill, New York, United States
Related Distances from Peekskill
Aleksandrow Lodzki, Łódzki, Poland