Distance from Peekskill to Alexandria
The shortest distance (air line) between Peekskill and Alexandria is 4,713.20 mi (7,585.16 km).
How far is Peekskill from Alexandria
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 22:57 (19.05.2025)
Alexandria is located in Teleorman, Romania within 43° 58' 6.96" N 25° 19' 59.88" E (43.9686, 25.3333) coordinates. The local time in Alexandria is 05:57 (20.05.2025)
The calculated flying distance from Alexandria to Alexandria is 4,713.20 miles which is equal to 7,585.16 km.
Peekskill, New York, United States
Related Distances from Peekskill
Alexandria, Teleorman, Romania