Distance from Peekskill to Altus
The shortest distance (air line) between Peekskill and Altus is 1,450.32 mi (2,334.06 km).
How far is Peekskill from Altus
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 14:33 (17.06.2025)
Altus is located in Oklahoma, United States within 34° 39' 23.4" N -100° 41' 38.04" W (34.6565, -99.3061) coordinates. The local time in Altus is 13:33 (17.06.2025)
The calculated flying distance from Altus to Altus is 1,450.32 miles which is equal to 2,334.06 km.
Peekskill, New York, United States
Related Distances from Peekskill
Altus, Oklahoma, United States