Distance from Peekskill to Boguszow-Gorce
The shortest distance (air line) between Peekskill and Boguszow-Gorce is 4,099.33 mi (6,597.24 km).
How far is Peekskill from Boguszow-Gorce
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 17:28 (17.05.2025)
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 23:28 (17.05.2025)
The calculated flying distance from Boguszow-Gorce to Boguszow-Gorce is 4,099.33 miles which is equal to 6,597.24 km.
Peekskill, New York, United States
Related Distances from Peekskill
Boguszow-Gorce, Wałbrzyski, Poland