Distance from Peekskill to Buggenhout
The shortest distance (air line) between Peekskill and Buggenhout is 3,620.60 mi (5,826.79 km).
How far is Peekskill from Buggenhout
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 03:20 (20.04.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 09:20 (20.04.2025)
The calculated flying distance from Buggenhout to Buggenhout is 3,620.60 miles which is equal to 5,826.79 km.
Peekskill, New York, United States
Related Distances from Peekskill
Buggenhout, Arr. Dendermonde, Belgium