Distance from Peekskill to Cesky Tesin
The shortest distance (air line) between Peekskill and Cesky Tesin is 4,227.41 mi (6,803.36 km).
How far is Peekskill from Cesky Tesin
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 07:41 (21.04.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 13:41 (21.04.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 4,227.41 miles which is equal to 6,803.36 km.
Peekskill, New York, United States
Related Distances from Peekskill
Cesky Tesin, Moravskoslezský kraj, Czechia