Distance from Peekskill to Dallgow-Doberitz
The shortest distance (air line) between Peekskill and Dallgow-Doberitz is 3,923.07 mi (6,313.57 km).
How far is Peekskill from Dallgow-Doberitz
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 10:31 (27.04.2025)
Dallgow-Doberitz is located in Havelland, Germany within 52° 31' 59.16" N 13° 3' 0" E (52.5331, 13.0500) coordinates. The local time in Dallgow-Doberitz is 16:31 (27.04.2025)
The calculated flying distance from Dallgow-Doberitz to Dallgow-Doberitz is 3,923.07 miles which is equal to 6,313.57 km.
Peekskill, New York, United States
Related Distances from Peekskill
Dallgow-Doberitz, Havelland, Germany