Distance from Peekskill to Doctor Phillips
The shortest distance (air line) between Peekskill and Doctor Phillips is 984.52 mi (1,584.43 km).
How far is Peekskill from Doctor Phillips
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 05:07 (20.06.2025)
Doctor Phillips is located in Florida, United States within 28° 26' 50.64" N -82° 30' 30.96" W (28.4474, -81.4914) coordinates. The local time in Doctor Phillips is 05:07 (20.06.2025)
The calculated flying distance from Doctor Phillips to Doctor Phillips is 984.52 miles which is equal to 1,584.43 km.
Peekskill, New York, United States
Related Distances from Peekskill
Doctor Phillips, Florida, United States