Distance from Peekskill to Faribault
The shortest distance (air line) between Peekskill and Faribault is 1,000.67 mi (1,610.42 km).
How far is Peekskill from Faribault
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 20:26 (20.06.2025)
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 19:26 (20.06.2025)
The calculated flying distance from Faribault to Faribault is 1,000.67 miles which is equal to 1,610.42 km.
Peekskill, New York, United States
Related Distances from Peekskill
Faribault, Minnesota, United States