Distance from Peekskill to Gornji Petrovci
The shortest distance (air line) between Peekskill and Gornji Petrovci is 4,237.36 mi (6,819.37 km).
How far is Peekskill from Gornji Petrovci
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 01:08 (22.05.2025)
Gornji Petrovci is located in Pomurska, Slovenia within 46° 48' 18" N 16° 13' 1.92" E (46.8050, 16.2172) coordinates. The local time in Gornji Petrovci is 07:08 (22.05.2025)
The calculated flying distance from Gornji Petrovci to Gornji Petrovci is 4,237.36 miles which is equal to 6,819.37 km.
Peekskill, New York, United States
Related Distances from Peekskill
Gornji Petrovci, Pomurska, Slovenia