Distance from Peekskill to Guaynabo
The shortest distance (air line) between Peekskill and Guaynabo is 1,648.56 mi (2,653.10 km).
How far is Peekskill from Guaynabo
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 13:06 (21.06.2025)
Guaynabo is located in Puerto Rico, United States within 18° 22' 59.52" N -67° 53' 11.76" W (18.3832, -66.1134) coordinates. The local time in Guaynabo is 14:06 (21.06.2025)
The calculated flying distance from Guaynabo to Guaynabo is 1,648.56 miles which is equal to 2,653.10 km.
Peekskill, New York, United States
Related Distances from Peekskill
Guaynabo, Puerto Rico, United States