Distance from Peekskill to Lukovica
The shortest distance (air line) between Peekskill and Lukovica is 4,197.48 mi (6,755.18 km).
How far is Peekskill from Lukovica
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 06:46 (22.05.2025)
Lukovica is located in Osrednjeslovenska, Slovenia within 46° 10' 6.96" N 14° 41' 21.12" E (46.1686, 14.6892) coordinates. The local time in Lukovica is 12:46 (22.05.2025)
The calculated flying distance from Lukovica to Lukovica is 4,197.48 miles which is equal to 6,755.18 km.
Peekskill, New York, United States
Related Distances from Peekskill
Lukovica, Osrednjeslovenska, Slovenia