Distance from Peekskill to Martinsburg
The shortest distance (air line) between Peekskill and Martinsburg is 248.05 mi (399.20 km).
How far is Peekskill from Martinsburg
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 17:37 (10.01.2026)
Martinsburg is located in West Virginia, United States within 39° 27' 29.52" N -78° 1' 20.64" W (39.4582, -77.9776) coordinates. The local time in Martinsburg is 17:37 (10.01.2026)
The calculated flying distance from Martinsburg to Martinsburg is 248.05 miles which is equal to 399.20 km.
Peekskill, New York, United States
Related Distances from Peekskill
Martinsburg, West Virginia, United States