Distance from Peekskill to Maxhutte-Haidhof
The shortest distance (air line) between Peekskill and Maxhutte-Haidhof is 3,990.40 mi (6,421.93 km).
How far is Peekskill from Maxhutte-Haidhof
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 00:16 (30.04.2025)
Maxhutte-Haidhof is located in Schwandorf, Germany within 49° 12' 0" N 12° 5' 60" E (49.2000, 12.1000) coordinates. The local time in Maxhutte-Haidhof is 06:16 (30.04.2025)
The calculated flying distance from Maxhutte-Haidhof to Maxhutte-Haidhof is 3,990.40 miles which is equal to 6,421.93 km.
Peekskill, New York, United States
Related Distances from Peekskill
Maxhutte-Haidhof, Schwandorf, Germany