Distance from Peekskill to Monkseaton
The shortest distance (air line) between Peekskill and Monkseaton is 3,309.06 mi (5,325.42 km).
How far is Peekskill from Monkseaton
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 14:36 (21.12.2025)
Monkseaton is located in Tyneside, United Kingdom within 55° 2' 34.8" N -2° 32' 27.6" W (55.0430, -1.4590) coordinates. The local time in Monkseaton is 19:36 (21.12.2025)
The calculated flying distance from Monkseaton to Monkseaton is 3,309.06 miles which is equal to 5,325.42 km.
Peekskill, New York, United States
Related Distances from Peekskill
Monkseaton, Tyneside, United Kingdom