Distance from Peekskill to Sajoszentpeter
The shortest distance (air line) between Peekskill and Sajoszentpeter is 4,363.84 mi (7,022.92 km).
How far is Peekskill from Sajoszentpeter
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 18:23 (06.05.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 00:23 (07.05.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 4,363.84 miles which is equal to 7,022.92 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary