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      Distance from Peekskill to San Ferdinando di Puglia

      The shortest distance (air line) between Peekskill and San Ferdinando di Puglia is 4,434.14 mi (7,136.06 km).

      How far is Peekskill from San Ferdinando di Puglia

      Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 01:18 (14.05.2025)

      San Ferdinando di Puglia is located in Barletta-Andria-Trani, Italy within 41° 17' 60" N 16° 4' 0.12" E (41.3000, 16.0667) coordinates. The local time in San Ferdinando di Puglia is 07:18 (14.05.2025)

      The calculated flying distance from San Ferdinando di Puglia to San Ferdinando di Puglia is 4,434.14 miles which is equal to 7,136.06 km.

      Peekskill, New York, United States

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      San Ferdinando di Puglia, Barletta-Andria-Trani, Italy

      Related Distances to San Ferdinando di Puglia