Distance from Peekskill to San Lazzaro di Savena
The shortest distance (air line) between Peekskill and San Lazzaro di Savena is 4,118.40 mi (6,627.92 km).
How far is Peekskill from San Lazzaro di Savena
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 01:04 (14.05.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 07:04 (14.05.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,118.40 miles which is equal to 6,627.92 km.
Peekskill, New York, United States
Related Distances from Peekskill
San Lazzaro di Savena, Bologna, Italy