Distance from Peekskill to San Luis
The shortest distance (air line) between Peekskill and San Luis is 2,311.49 mi (3,719.99 km).
How far is Peekskill from San Luis
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 20:39 (21.12.2025)
San Luis is located in Arizona, United States within 32° 29' 27.96" N -115° 17' 27.96" W (32.4911, -114.7089) coordinates. The local time in San Luis is 18:39 (21.12.2025)
The calculated flying distance from San Luis to San Luis is 2,311.49 miles which is equal to 3,719.99 km.
Peekskill, New York, United States
Related Distances from Peekskill
San Luis, Arizona, United States